Distance between Charlotte, North Carolina, USA and Aleksandrovsk-Sakhalinskiy, Sakhalin Oblast, Russia

9566 km = 5944 miles

We assume a spherical Earth as a close approximation of the true shape of the Earth (an oblate spheroid). The distance is calculated as great-circle or orthodromic distance between city centres on the surface of a sphere.

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Charlotte, USA

Country: USA
State: North Carolina
Charlotte’s coordinates: 35°13′37″ N, 80°50′35″ W
Population: 731,424
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Wikipedia article: Charlotte

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Aleksandrovsk-Sakhalinskiy, Russia

Country: Russia
Aleksandrovsk-Sakhalinskiy’s coordinates: 50°53′57″ N, 142°09′43″ E
Population: 12,024
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Wikipedia article: Aleksandrovsk-Sakhalinskiy

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