Geographic coordinates of Aleksandrovsk-Sakhalinskiy, Sakhalin Oblast, Russia
Longitude: 142°09′43″ E
Elevation above sea level: 36 m = 118 ft
Coordinates of Aleksandrovsk-Sakhalinskiy in decimal degrees
Coordinates of Aleksandrovsk-Sakhalinskiy in degrees and decimal minutes
Longitude: 142°9.729′ E
UTM coordinates of Aleksandrovsk-Sakhalinskiy
Geographic coordinate systems
WGS 84 coordinate reference system is the latest revision of the World Geodetic System, which is used in mapping and navigation, including GPS satellite navigation system (the Global Positioning System).
Geographic coordinates (latitude and longitude) define a position on the Earth’s surface. Coordinates are angular units. The canonical form of latitude and longitude representation uses degrees (°), minutes (′), and seconds (″). GPS systems widely use coordinates in degrees and decimal minutes, or in decimal degrees.
Latitude varies from −90° to 90°. The latitude of the Equator is 0°; the latitude of the South Pole is −90°; the latitude of the North Pole is 90°. Positive latitude values correspond to the geographic locations north of the Equator (abbrev. N). Negative latitude values correspond to the geographic locations south of the Equator (abbrev. S).
Longitude is counted from the prime meridian (IERS Reference Meridian for WGS 84) and varies from −180° to 180°. Positive longitude values correspond to the geographic locations east of the prime meridian (abbrev. E). Negative longitude values correspond to the geographic locations west of the prime meridian (abbrev. W).
UTM or Universal Transverse Mercator coordinate system divides the Earth’s surface into 60 longitudinal zones. The coordinates of a location within each zone are defined as a planar coordinate pair related to the intersection of the equator and the zone’s central meridian, and measured in meters.
Elevation above sea level is a measure of a geographic location’s height. We are using the global digital elevation model GTOPO30.
Aleksandrovsk-Sakhalinskiy, Sakhalin Oblast, Russia
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