Distance between San Jose, California, USA and Lexington-Fayette, Kentucky, USA
3276 km = 2036 miles
We assume a spherical Earth as a close approximation of the true shape of the Earth (an oblate spheroid). The distance is calculated as great-circle or orthodromic distance between city centres on the surface of a sphere.
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San Jose, USA
Country: USAState: California
San Jose’s coordinates: 37°20′21″ N, 121°53′41″ W
Population: 945,942
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Wikipedia article: San Jose
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Lexington-Fayette, USA
Country: USAState: Kentucky
Lexington-Fayette’s coordinates: 38°02′59″ N, 84°27′30″ W
Population: 295,803
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Wikipedia article: Lexington-Fayette
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