Distance between San Antonio, Texas, USA and Lyakhavichy, Belarus

9419 km = 5852 miles

We assume a spherical Earth as a close approximation of the true shape of the Earth (an oblate spheroid). The distance is calculated as great-circle or orthodromic distance between city centres on the surface of a sphere.

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San Antonio, USA

Country: USA
State: Texas
San Antonio’s coordinates: 29°25′26″ N, 98°29′37″ W
Population: 1,327,407
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Wikipedia article: San Antonio

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Lyakhavichy, Belarus

Country: Belarus
Lyakhavichy’s coordinates: 53°02′19″ N, 26°15′56″ E
Population: 11,500
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Wikipedia article: Lyakhavichy

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