Distance between Jacksonville, Florida, USA and Kuznetsovsk, Ukraine
8505 km = 5285 miles
We assume a spherical Earth as a close approximation of the true shape of the Earth (an oblate spheroid). The distance is calculated as great-circle or orthodromic distance between city centres on the surface of a sphere.
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Jacksonville, USA
Country: USAState: Florida
Jacksonville’s coordinates: 30°19′55″ N, 81°39′20″ W
Population: 821,784
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Kuznetsovsk, Ukraine
Country: UkraineKuznetsovsk’s coordinates: 51°40′59″ N, 25°52′00″ E
Population: 40,000
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