Distance between Jacksonville, Florida, USA and Verkhneye Sinevodnoye, Ukraine
8518 km = 5293 miles
We assume a spherical Earth as a close approximation of the true shape of the Earth (an oblate spheroid). The distance is calculated as great-circle or orthodromic distance between city centres on the surface of a sphere.
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Jacksonville, USA
Country: USAState: Florida
Jacksonville’s coordinates: 30°19′55″ N, 81°39′20″ W
Population: 821,784
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Verkhneye Sinevodnoye, Ukraine
Country: UkraineVerkhneye Sinevodnoye’s coordinates: 49°06′11″ N, 23°35′27″ E
Population: 3,555
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