Distance between Jacksonville, Florida, USA and Bogatyye Saby, Republic of Tatarstan, Russia
9411 km = 5847 miles
We assume a spherical Earth as a close approximation of the true shape of the Earth (an oblate spheroid). The distance is calculated as great-circle or orthodromic distance between city centres on the surface of a sphere.
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Jacksonville, USA
Country: USAState: Florida
Jacksonville’s coordinates: 30°19′55″ N, 81°39′20″ W
Population: 821,784
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Bogatyye Saby, Russia
Country: RussiaBogatyye Saby’s coordinates: 56°00′36″ N, 50°26′53″ E
Population: 7,209
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