Distance between Jacksonville, Florida, USA and Petropavlovsk-Kamchatskiy, Kamchatka Krai, Russia

9081 km = 5643 miles

We assume a spherical Earth as a close approximation of the true shape of the Earth (an oblate spheroid). The distance is calculated as great-circle or orthodromic distance between city centres on the surface of a sphere.

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Jacksonville, USA

Country: USA
State: Florida
Jacksonville’s coordinates: 30°19′55″ N, 81°39′20″ W
Population: 821,784
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Wikipedia article: Jacksonville

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Petropavlovsk-Kamchatskiy, Russia

Country: Russia
Petropavlovsk-Kamchatskiy’s coordinates: 53°02′39″ N, 158°39′02″ E
Population: 187,282
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Wikipedia article: Petropavlovsk-Kamchatskiy

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