Distance between Sevastopol, Ukraine and Jacksonville Beach, Florida, USA
9411 km = 5848 miles
We assume a spherical Earth as a close approximation of the true shape of the Earth (an oblate spheroid). The distance is calculated as great-circle or orthodromic distance between city centres on the surface of a sphere.
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Sevastopol, Ukraine
Country: UkraineSevastopol’s coordinates: 44°35′19″ N, 33°31′20″ E
Population: 416,263
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Wikipedia article: Sevastopol
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Jacksonville Beach, USA
Country: USAState: Florida
Jacksonville Beach’s coordinates: 30°17′40″ N, 81°23′35″ W
Population: 21,362
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Wikipedia article: Jacksonville Beach
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