Distance between San Antonio, Texas, USA and Moskovskiy, Tajikistan

12455 km = 7739 miles

We assume a spherical Earth as a close approximation of the true shape of the Earth (an oblate spheroid). The distance is calculated as great-circle or orthodromic distance between city centres on the surface of a sphere.

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San Antonio, USA

Country: USA
State: Texas
San Antonio’s coordinates: 29°25′26″ N, 98°29′37″ W
Population: 1,327,407
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Wikipedia article: San Antonio

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Moskovskiy, Tajikistan

Country: Tajikistan
Moskovskiy’s coordinates: 37°36′33″ N, 68°34′51″ E
Population: 22,100
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Wikipedia article: Moskovskiy

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