Distance between Jacksonville, Florida, USA and Slavskoye, Ukraine

8524 km = 5296 miles

We assume a spherical Earth as a close approximation of the true shape of the Earth (an oblate spheroid). The distance is calculated as great-circle or orthodromic distance between city centres on the surface of a sphere.

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Jacksonville, USA

Country: USA
State: Florida
Jacksonville’s coordinates: 30°19′55″ N, 81°39′20″ W
Population: 821,784
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Wikipedia article: Jacksonville

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Slavskoye, Ukraine

Country: Ukraine
Slavskoye’s coordinates: 48°50′50″ N, 23°26′45″ E
Population: 6,436
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Wikipedia article: Slavskoye

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