Distance between Jacksonville, Florida, USA and Slavskoye, Ukraine
8524 km = 5296 miles
We assume a spherical Earth as a close approximation of the true shape of the Earth (an oblate spheroid). The distance is calculated as great-circle or orthodromic distance between city centres on the surface of a sphere.
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Jacksonville, USA
Country: USAState: Florida
Jacksonville’s coordinates: 30°19′55″ N, 81°39′20″ W
Population: 821,784
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Slavskoye, Ukraine
Country: UkraineSlavskoye’s coordinates: 48°50′50″ N, 23°26′45″ E
Population: 6,436
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