Distance between Luxor, Egypt and San Angelo, Texas, USA

11953 km = 7427 miles

We assume a spherical Earth as a close approximation of the true shape of the Earth (an oblate spheroid). The distance is calculated as great-circle or orthodromic distance between city centres on the surface of a sphere.

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Luxor, Egypt

Country: Egypt
Luxor’s coordinates: 25°41′56″ N, 32°38′31″ E
Population: 422,407
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Wikipedia article: Luxor

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Find out the distance between Luxor and the North Pole, the South Pole, the Equator, the Tropic of Cancer, the Tropic of Capricorn, the Arctic Circle, the Antarctic Circle

San Angelo, USA

Country: USA
State: Texas
San Angelo’s coordinates: 31°27′49″ N, 100°26′13″ W
Population: 93,200
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Wikipedia article: San Angelo

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Find out the distance between San Angelo and the North Pole, the South Pole, the Equator, the Tropic of Cancer, the Tropic of Capricorn, the Arctic Circle, the Antarctic Circle