Distance between Ashgabat, Turkmenistan and Jacksonville Beach, Florida, USA

11366 km = 7062 miles

We assume a spherical Earth as a close approximation of the true shape of the Earth (an oblate spheroid). The distance is calculated as great-circle or orthodromic distance between city centres on the surface of a sphere.

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Ashgabat, Turkmenistan

Country: Turkmenistan
Ashgabat’s coordinates: 37°57′00″ N, 58°22′59″ E
Population: 727,700
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Wikipedia article: Ashgabat

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Jacksonville Beach, USA

Country: USA
State: Florida
Jacksonville Beach’s coordinates: 30°17′40″ N, 81°23′35″ W
Population: 21,362
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Wikipedia article: Jacksonville Beach

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Find out the distance between Jacksonville Beach and the North Pole, the South Pole, the Equator, the Tropic of Cancer, the Tropic of Capricorn, the Arctic Circle, the Antarctic Circle