Distance between Yekaterinburg, Sverdlovsk Oblast, Russia and Lindenhurst, New York, USA
8355 km = 5192 miles
We assume a spherical Earth as a close approximation of the true shape of the Earth (an oblate spheroid). The distance is calculated as great-circle or orthodromic distance between city centres on the surface of a sphere.
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Yekaterinburg, Russia
Country: RussiaYekaterinburg’s coordinates: 56°51′06″ N, 60°36′43″ E
Population: 1,349,772
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Lindenhurst, USA
Country: USAState: New York
Lindenhurst’s coordinates: 40°41′12″ N, 73°22′24″ W
Population: 27,253
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