Distance between Jacksonville, Florida, USA and Gvardeysk, Kaliningrad Oblast, Russia

8063 km = 5010 miles

We assume a spherical Earth as a close approximation of the true shape of the Earth (an oblate spheroid). The distance is calculated as great-circle or orthodromic distance between city centres on the surface of a sphere.

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Jacksonville, USA

Country: USA
State: Florida
Jacksonville’s coordinates: 30°19′55″ N, 81°39′20″ W
Population: 821,784
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Wikipedia article: Jacksonville

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Gvardeysk, Russia

Country: Russia
Gvardeysk’s coordinates: 54°38′51″ N, 21°03′54″ E
Population: 13,088
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Wikipedia article: Gvardeysk

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