Distance between Vladivostok, Primorsky Krai, Russia and Sandy City, Utah, USA
8738 km = 5429 miles
We assume a spherical Earth as a close approximation of the true shape of the Earth (an oblate spheroid). The distance is calculated as great-circle or orthodromic distance between city centres on the surface of a sphere.
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Vladivostok, Russia
Country: RussiaVladivostok’s coordinates: 43°06′20″ N, 131°52′24″ E
Population: 587,022
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Wikipedia article: Vladivostok
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Sandy City, USA
Country: USAState: Utah
Sandy City’s coordinates: 40°35′29″ N, 111°53′02″ W
Population: 87,461
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Wikipedia article: Sandy City
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